ICSE Class 10

ICSE Class 10 Similarity of Triangles — Mock Test (2027)

Free online mock test for Similarity of Triangles (ICSE Class 10 Mathematics) — 20 competency-based questions based on the latest CISCE 2027 syllabus, with instant marking. Try the samples below, then take the full test free.

What to expect: This mock test covers key concepts from the Similarity of Triangles chapter — including application-based and competency-focused questions aligned with how ICSE actually sets the paper.

Tip: Attempt without notes first to identify gaps, then review explanations for any wrong answers. Retake after a few days for best retention.

Sample questions

  1. 1.A line PQ is drawn parallel to the side BC of Δ ABC which cuts side AB at P and side AC at Q. If AB = 9.0 cm, CA = 6.0 cm, and AQ = 4.2 cm, find the length of AP.
    • A.4.2 cm
    • B.6.3 cm
    • C.5.6 cm
    • D.7.0 cm
  2. 2.An aeroplane is 30 m long and its model is 15 cm long. If the total outer surface area of the model is 150 cm², find the cost of painting the outer surface of the aeroplane at the rate of ₹ 120 per sq. m. Given that 50 sq. m of the surface of the aeroplane is left for windows.
  3. 3.Assertion (A): The ratio of the areas of two similar triangles is equal to the ratio of the squares of their corresponding sides. Reason (R): If two triangles are similar, their corresponding sides are proportional. Which of the following is correct regarding the assertion and reason above?
    • A.Both assertion (A) and reason (R) are true, and reason (R) is the correct explanation of assertion (A).
    • B.Both assertion (A) and reason (R) are true, but reason (R) is not the correct explanation of assertion (A).
    • C.Assertion (A) is true, but reason (R) is false.
    • D.Assertion (A) is false, but reason (R) is true.
  4. 4.The area of two similar triangles are 48 cm² and 75 cm² respectively. If the altitude of the first triangle be 3.6 cm, find the corresponding altitude of the other.
  5. 5.Triangle ABC is similar to triangle PQR. If AD and PM are altitudes of the two triangles, which of the following correctly relates the sides and altitudes of these triangles?
    • A.AB/PQ = AD/PM because corresponding sides and altitudes of similar triangles are proportional.
    • B.AB/PQ = PM/AD because altitudes are inversely proportional to the sides in similar triangles.
    • C.AB + PQ = AD + PM because the sum of sides and altitudes must be equal in similar triangles.
    • D.AB × PQ = AD × PM because the product of sides and altitudes is constant in similar triangles.

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